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The one with super has greater flexibility How to call super ().super () in overridden method (grandparent method) [duplicate] asked 13 years, 2 months ago modified 8 years, 9 months ago viewed 46k times The call chain for the methods can be intercepted and functionality injected.

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In fact, multiple inheritance is the only case where super() is of any use 'super' object has no attribute do_something class parent I would not recommend using it with classes using linear inheritance, where it's just useless overhead.

Super() lets you avoid referring to the base class explicitly, which can be nice

But the main advantage comes with multiple inheritance, where all sorts of fun stuff can happen. Super e>) says that it's some type which is an ancestor (superclass) of e Extends e>) says that it's some type which is a subclass of e (in both cases e itself is okay.) so the constructor uses the

Extends e form so it guarantees that when it fetches values from the collection, they will all be e or some subclass (i.e As for chaining super::super, as i mentionned in the question, i have still to find an interesting use to that For now, i only see it as a hack, but it was worth mentioning, if only for the differences with java (where you can't chain super). 'super' object has no attribute '__sklearn_tags__'

This occurs when i invoke the fit method on the randomizedsearchcv object

I attempted to tune the hyperparameters of an xgbregressor. What is the difference between list< I used to use list< Extends t>, but it does not allow me to add elements to it list.add (e), whereas the li.

I'm currently learning about class inheritance in my java course and i don't understand when to use the super() call I found this example of code where super.variable is used I wrote the following code When i try to run it as at the end of the file i get this stacktrace