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After running the following command If it is a one off then substituting in newline characters as in one of the answers would. How are you building the package and what is your expression?
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You'll need to complete a few actions and gain 15 reputation points before being able to upvote Unfortunately i have no idea of the existence of such a tool, though it would not be hard to write Upvoting indicates when questions and answers are useful
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Instead, you can save this post to reference later. The problem comes from the very first line in your makefile Link this causes make to try to figure out how to create link But you don’t have a cc.exe command, so it fails — that’s the missing file
I want to install an older version of package <x>, and when i use dnf it only shows the current version of the package <x> Is there any way to install an older versions using dnf ? You should note that libpython3.6m.so is not in the output of ldconfig The output mentions libpython3.6m.so.1.0, which is not the same
If you don't have the development package, you can create a symlink libpython3.6m.so to libpython3.6m.so.1.0
Besides, as has already been mentioned, the compiler and the linker don't care for ld.so.conf. I am working on a new centos 8 server to replace an aging centos 6 server Most everything is working and i am having the primary users test out everything they use the server for Ld is the linker, i.e
The program that ties together the code that you wrote with the preexisting library code Libc is the c standard library, which is automatically linked in every program unless you explicitly request that it isn't (which is rarely done except for. I am thinking that a tool that can only do search and replace, but not any more complex regex, would be faster It would also not benefit from doing a line at a time, so would not choke on this file
